If the detector spacing is 30 feet, what is the maximum distance from any ceiling point to the nearest detector?

Unlock all questions

This demo includes only 20 questions. Upgrade to access hundreds of questions, flashcards, exam simulations, and disable ads.

Full question bankExam simulationsFlashcards
From $24.99Unlock all

Pass the California Alarm Company Operator Exam. Study with flashcards and multiple choice questions, each with hints and explanations. Prepare for your exam with confidence!

Multiple Choice

If the detector spacing is 30 feet, what is the maximum distance from any ceiling point to the nearest detector?

Explanation:
Detectors arranged with equal spacing on the ceiling create square cells. The farthest point from any detector sits at the center of one of these squares. Half the spacing is 15 feet, so the distance from the center to a detector forms a right triangle with legs of 15 feet. The distance is sqrt(15^2 + 15^2) = sqrt(450) ≈ 21.2 feet, which rounds to about 21 feet. Therefore, the maximum distance is roughly 21 feet.

Detectors arranged with equal spacing on the ceiling create square cells. The farthest point from any detector sits at the center of one of these squares. Half the spacing is 15 feet, so the distance from the center to a detector forms a right triangle with legs of 15 feet. The distance is sqrt(15^2 + 15^2) = sqrt(450) ≈ 21.2 feet, which rounds to about 21 feet. Therefore, the maximum distance is roughly 21 feet.

More Multiple Choice Questions
Subscribe

Get the latest from Examzify

You can unsubscribe at any time. Read our privacy policy