If the spacing between detectors is 9.1 m (30 ft), the maximum distance any ceiling point can be from a detector is approximately how many feet?

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Pass the California Alarm Company Operator Exam. Study with flashcards and multiple choice questions, each with hints and explanations. Prepare for your exam with confidence!

Multiple Choice

If the spacing between detectors is 9.1 m (30 ft), the maximum distance any ceiling point can be from a detector is approximately how many feet?

Explanation:
When detectors are spaced evenly, the farthest point on the ceiling from any detector sits at the center of a square formed by four detectors at the corners. The distance from that center to a detector is half the square’s diagonal. With a 30 ft spacing, the diagonal is 30√2 ft, so half the diagonal is (30√2)/2 = 15√2 ≈ 21.2 ft. So the maximum distance is about 21 ft, which matches the closest option.

When detectors are spaced evenly, the farthest point on the ceiling from any detector sits at the center of a square formed by four detectors at the corners. The distance from that center to a detector is half the square’s diagonal. With a 30 ft spacing, the diagonal is 30√2 ft, so half the diagonal is (30√2)/2 = 15√2 ≈ 21.2 ft. So the maximum distance is about 21 ft, which matches the closest option.

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