What fraction of the detector spacing determines the maximum allowed distance from a point on the ceiling to the nearest detector?

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Pass the California Alarm Company Operator Exam. Study with flashcards and multiple choice questions, each with hints and explanations. Prepare for your exam with confidence!

Multiple Choice

What fraction of the detector spacing determines the maximum allowed distance from a point on the ceiling to the nearest detector?

Explanation:
With detectors arranged on a regular ceiling grid, the point farthest from any detector sits at the center of a square formed by four neighboring detectors. The distance from that center to a detector at a corner is the hypotenuse of a right triangle with legs x/2 and x/2, giving sqrt[(x/2)^2 + (x/2)^2] = (√2/2) x ≈ 0.707x. So the maximum distance to the nearest detector is about 0.7x.

With detectors arranged on a regular ceiling grid, the point farthest from any detector sits at the center of a square formed by four neighboring detectors. The distance from that center to a detector at a corner is the hypotenuse of a right triangle with legs x/2 and x/2, giving sqrt[(x/2)^2 + (x/2)^2] = (√2/2) x ≈ 0.707x. So the maximum distance to the nearest detector is about 0.7x.

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